10x^2+X=12.6

Solution for 10x^2+X=12.6 equation:

10x^2+x=12.6

We move all terms to the left:

10x^2+x-(12.6)=0

We add all the numbers together, and all the variables

10x^2+x-12.6=0

a = 10; b = 1; c = -12.6;
Δ = b2-4ac
Δ = 12-4·10·(-12.6)
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{505}}{2*10}=\frac{-1-\sqrt{505}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{505}}{2*10}=\frac{-1+\sqrt{505}}{20}
$